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Jun 2, 2019 at 14:15 comment added fedja Only on a big set. On a small set $|u|$ can be as far from $1$ as you want.
Jun 2, 2019 at 14:10 comment added R. N. Marley But always, independently of the dimension, $|u|$ is close to $1$ if the energy is small, isnt it? The problem is that $\theta $ is not $H^1(T^N)$ when $N>1$. Am I right?
Jun 1, 2019 at 22:29 comment added fedja Only in dimension $1$. In higher dimensions you can create a function with arbitrarily small energy that vanishes on an open set, after which you can change it a bit on that open set to make the argument $\theta$ behaving in a bad way.
Jun 1, 2019 at 17:20 history asked R. N. Marley CC BY-SA 4.0