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Martin Sleziak
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I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programmingsemidefinite programming, as suggested by David Speyer in his answer.

It is now known that the group $\mathrm{Aut}(F_n)$ has property (T) iff $n\geq 4$.

For $n\geq 5$ this is shown in Kaluba-Kielak-Nowak. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa and the case $n=4$ was recently settled in Nitsche. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya. $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T). This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

It is now known that the group $\mathrm{Aut}(F_n)$ has property (T) iff $n\geq 4$.

For $n\geq 5$ this is shown in Kaluba-Kielak-Nowak. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa and the case $n=4$ was recently settled in Nitsche. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya. $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T). This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

It is now known that the group $\mathrm{Aut}(F_n)$ has property (T) iff $n\geq 4$.

For $n\geq 5$ this is shown in Kaluba-Kielak-Nowak. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa and the case $n=4$ was recently settled in Nitsche. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya. $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T). This is all quite remarkable.

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Uri Bader
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I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

SeeIt is now known that the group $\mathrm{Aut}(F_n)$ has property (T) iff $n\geq 4$.

For $n\geq 5$ this is shown in Kaluba-Kielak-Nowak for a proof that $\mathrm{Aut}(F_n)$ has (T) for $n\geq 5$. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa and the case $n=4$ was recently settled in Nitsche. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.

We note that   $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T), and the case for $\mathrm{Aut}(F_4)$ is still open. This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

See Kaluba-Kielak-Nowak for a proof that $\mathrm{Aut}(F_n)$ has (T) for $n\geq 5$. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.

We note that $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T), and the case for $\mathrm{Aut}(F_4)$ is still open. This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

It is now known that the group $\mathrm{Aut}(F_n)$ has property (T) iff $n\geq 4$.

For $n\geq 5$ this is shown in Kaluba-Kielak-Nowak. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa and the case $n=4$ was recently settled in Nitsche. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.  $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T). This is all quite remarkable.

added 247 characters in body
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Uri Bader
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I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to proveprovide a computer based proof for property (T) using the Ozawa's equationOzawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

See Kaluba-Kielak-Nowak for a proof that $\mathrm{Aut}(F_n)$ has (T) for $n\geq 5$. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.

We note that $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T), and the case for $\mathrm{Aut}(F_4)$ is still open. This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to prove property (T) using the Ozawa's equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved.

See Kaluba-Kielak-Nowak for a proof that $\mathrm{Aut}(F_n)$ has (T) for $n\geq 5$. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.

We note that $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T), and the case for $\mathrm{Aut}(F_4)$ is still open. This is all quite remarkable.

I think it is appropriate to let MO users know (the OP himself knows it well) that this question was recently solved: it is feasible to provide a computer based proof for property (T) using the Ozawa Equation and this method was applied successfully to the groups mentioned in the question. In particular, the famous open problem alluded to above is now solved. The computation is done via semidefinite programming, as suggested by David Speyer in his answer.

See Kaluba-Kielak-Nowak for a proof that $\mathrm{Aut}(F_n)$ has (T) for $n\geq 5$. The case $n=5$ was treated earlier in Kaluba-Nowak-Ozawa. Some earlier positive results were obtained in Netzer-Thom and Fujiwara-Kabaya.

We note that $\mathrm{Aut}(F_2)$ and $\mathrm{Aut}(F_3)$ are known not to have (T), and the case for $\mathrm{Aut}(F_4)$ is still open. This is all quite remarkable.

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Uri Bader
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