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Nov 8, 2023 at 15:08 comment added Ben Sprott Every commutative monoid is uniquely an $\mathbb{N}$-semimodule in the same way that an abelian group is a $\mathbb {Z}$-module.
Nov 8, 2023 at 15:00 comment added Ben Sprott @MartinBrandenburg I think I mean a semimodule over the natural numbers. That's what I mean by N-module.
Oct 30, 2023 at 4:37 comment added Alec Rhea @MartinBrandenburg Group carrying an N-action appropriately compatible with the group structure would obviously be the naive guess; does this not work out for some reason?
Oct 29, 2023 at 20:50 comment added Martin Brandenburg What is an N-module here?
Oct 29, 2023 at 17:24 history edited YCor CC BY-SA 4.0
removed capitals from title
Oct 29, 2023 at 15:39 history edited Ben Sprott CC BY-SA 4.0
edited body
May 31, 2019 at 3:30 history edited user64494 CC BY-SA 4.0
The style of the title is improved.
May 30, 2019 at 23:05 history edited Ben Sprott CC BY-SA 4.0
added 486 characters in body
May 30, 2019 at 21:53 comment added Dylan Wilson You can’t compose monads and get another monad- you have to specify a ‘distributive’ law between them to endow the composite with the structure of a monad.
May 30, 2019 at 16:26 history asked Ben Sprott CC BY-SA 4.0