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May 30, 2019 at 12:59 comment added Salvatore Siciliano Ciao Marco, in fact you are interpreting uncorrectly my question...First of all, I am not assuming that the simple Lie algebra $\mathfrak{g}$ is finite-dimensional and defined over a field of characteristic zero, so it is not true in general that $H^1(\mathfrak{g},\mathfrak{g} )=0$. Second, $L$ is by hypothesis a central extension of a simple Lie algebra because this is just the specific situation I am interested in.
May 30, 2019 at 1:42 history answered Marco Farinati CC BY-SA 4.0