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May 27, 2019 at 17:28 vote accept Dominic van der Zypen
May 27, 2019 at 16:50 answer added Lucia timeline score: 11
May 27, 2019 at 15:45 comment added Gerhard Paseman This is almost a duplicate of my question exact packing of the harmonic series. I conjecture (and probably am not the first to do so) that the answer is O(exp(k+1)). Further, I suspect a minimal set has all its members with denominators less than exp(k+1). Gerhard "Whose Line Is It Anyway?" Paseman, 2019.05.27.
May 27, 2019 at 14:20 history edited Dominic van der Zypen CC BY-SA 4.0
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May 27, 2019 at 14:20 comment added Dominic van der Zypen Thanks @FedorPetrov I will change the question!
May 27, 2019 at 12:45 comment added Fedor Petrov @DominicvanderZypen I suggest to change the question to "what is the asymptotic growth of $m(k)$" (even if the exponential lower bound is enough for you purpose, I think it is quite interesting in general to hold here).
May 27, 2019 at 12:01 comment added Gerry Myerson Ernie Croot has some papers about Egyptian fractions that you might find worth a look.
May 27, 2019 at 11:47 comment added Gerald Edgar ... but a comment there does mention the exponential lower bound.
May 27, 2019 at 10:51 comment added Gerald Edgar The keyword for this is "Egyptian fractions". A related question is at math.se ... math.stackexchange.com/q/3185675/442 ... no "answer" is given there, either.
May 27, 2019 at 10:38 comment added Dominic van der Zypen Thanks @FedorPetrov, can you post this as an answer so we can close this thread?
May 27, 2019 at 10:16 comment added Fedor Petrov The sum of $N$ different Egyptian fractions (fractions with numerator 1 and positive integer denominator) is at most $\log N+O(1)$, that implies the exponential lower bound for $m(k)$.
May 27, 2019 at 10:05 review Close votes
May 27, 2019 at 21:53
May 27, 2019 at 9:59 comment added Dominic van der Zypen Apologies to @GeraldEdgar, I changed the question (it also contained a typo).
May 27, 2019 at 9:58 comment added vidyarthi I think this is somewhat related to harmonic numbers and the euler constant
May 27, 2019 at 9:50 history edited Dominic van der Zypen CC BY-SA 4.0
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May 27, 2019 at 9:49 comment added Gerald Edgar You re asking in the wrong forum.
May 27, 2019 at 9:47 history asked Dominic van der Zypen CC BY-SA 4.0