Timeline for Does fractallity depend on the Riemannian metric?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| May 19, 2019 at 21:02 | vote | accept | Ali Taghavi | ||
| May 18, 2019 at 22:05 | comment | added | André Henriques | I expect the answer to be "no" because Hausdorff dimension is invariant under diffeomorphisms. | |
| May 18, 2019 at 22:05 | answer | added | Piotr Hajlasz | timeline score: 6 | |
| May 18, 2019 at 21:08 | comment | added | Ali Taghavi | @AndréHenriques Why do you expect the answer is "no"? | |
| May 18, 2019 at 20:06 | comment | added | Ali Taghavi | @AndréHenriques Now I revise the question. | |
| May 18, 2019 at 20:05 | review | Close votes | |||
| May 20, 2019 at 20:13 | |||||
| May 18, 2019 at 19:59 | history | edited | Ali Taghavi | CC BY-SA 4.0 |
edited body
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| May 18, 2019 at 19:39 | history | edited | Ali Taghavi | CC BY-SA 4.0 |
added 315 characters in body
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| May 18, 2019 at 19:31 | comment | added | Ali Taghavi | @AndréHenriques Thanks for your attention to my question. A fractal is a set whose topological dimension is not equal to its Hausdorff dimension. | |
| May 18, 2019 at 19:27 | comment | added | André Henriques | Under any mathematically formal definition of "fractal", I would expect the answer to be "no". But please: do provide a definition of the word "fractal". Without a definition, it is not possible to answer the question, because the terms in the question are not well defined. | |
| May 18, 2019 at 19:10 | history | asked | Ali Taghavi | CC BY-SA 4.0 |