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May 18, 2019 at 6:37 vote accept sharpe
May 18, 2019 at 6:29 comment added sharpe I see! Thank you very much for teaching me very carefully.
May 18, 2019 at 6:26 comment added fedja It is just Koebe 1/4 theorem for univalent functions.
May 18, 2019 at 6:21 comment added sharpe Thank you for your very kind reply. For the proof, you use a Harnack chain with length $N$. For the construction of this chain, you use the definition of John-domain, right? I would like to ask one more question, why is $|\Phi'(w)|$ and $d/(1-|w|)$ comparable? This is a consequence of a boundary Harnack principle? Indeed, $d/(1-|w|)$ is regarded as a ratio of harmonic functions.
May 17, 2019 at 20:46 history answered fedja CC BY-SA 4.0