Timeline for Finite sum involving root of unity
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| May 17, 2019 at 22:14 | history | edited | heynman | CC BY-SA 4.0 |
deleted 6 characters in body
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| May 17, 2019 at 18:36 | comment | added | LSpice | @alpoge, now I want to see if I can get the sign on my office changed to Prof. @LSpice. :-) | |
| May 17, 2019 at 18:27 | comment | added | alpoge | Hi Prof. @LSpice! I’m was referring to the last display (in order to get rid of the denominator) but I absolutely agree! It’d have been easier to just start that way (note that q is still prime to 2p). | |
| May 17, 2019 at 17:22 | comment | added | LSpice | @alpoge, it should be taking $r \equiv a q \pmod{2p}$, not just $r \equiv a q \pmod p$, right? Otherwise it seems there is a sign issue. | |
| May 17, 2019 at 16:28 | history | edited | Max Alekseyev | CC BY-SA 4.0 |
added 14 characters in body
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| S May 17, 2019 at 16:19 | history | suggested | user64494 | CC BY-SA 4.0 |
A typo in the title is corrected.
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| May 17, 2019 at 16:10 | review | Close votes | |||
| May 21, 2019 at 20:44 | |||||
| May 17, 2019 at 16:02 | comment | added | alpoge | Hey so r is a multiple of q modulo p/(p,\sigma) so replace r with aq and now it’s easy to divide the denominator into the numerator and sum the resulting geometric series. | |
| May 17, 2019 at 15:48 | review | Suggested edits | |||
| S May 17, 2019 at 16:19 | |||||
| May 17, 2019 at 15:25 | review | First posts | |||
| May 17, 2019 at 15:51 | |||||
| May 17, 2019 at 15:20 | history | asked | heynman | CC BY-SA 4.0 |