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May 17, 2019 at 10:18 comment added Gerald Edgar Of course, this is only one solution. There could be additional solutions where $f(n^k x)/n^k$ does not converge to $0$.
May 17, 2019 at 1:22 comment added mrplants Okay, walked through it on paper and just have a small edit: the answer is actually $\sum_{k=0}^\infty\left(\frac{1}{n}\right)^k\sin(n^kx)$
May 17, 2019 at 0:58 comment added mrplants Does this function have a name or any special properties? Anywhere I can learn more about this?
May 17, 2019 at 0:54 vote accept mrplants
May 17, 2019 at 0:54 comment added mrplants That's amazing. Thank you.
May 17, 2019 at 0:38 comment added Nick S @mrplants $$f(x)+\frac{1}{n}f(nx)=\sin(x)\\ \frac{1}{n}f(nx)+\frac{1}{n^2}f(n^2x)=\frac{1}{n}\sin(nx) \\\frac{1}{n^2}f(n^2x)+\frac{1}{n^3}f(n^3x)=\frac{1}{n^2} \sin(x) \\\...$$Now, first equation minus second plus third and so on...
May 17, 2019 at 0:33 comment added mrplants Can you provide details on how to solve this or point me to somewhere with more information? I'd like to learn more.
May 17, 2019 at 0:26 history answered Michael Renardy CC BY-SA 4.0