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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
May 29, 2019 at 9:04 history edited asd CC BY-SA 4.0
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S May 27, 2019 at 11:02 history bounty ended CommunityBot
S May 27, 2019 at 11:02 history notice removed CommunityBot
May 26, 2019 at 17:50 history edited asd CC BY-SA 4.0
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May 26, 2019 at 17:29 history edited asd CC BY-SA 4.0
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May 26, 2019 at 17:19 history edited asd CC BY-SA 4.0
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May 26, 2019 at 17:09 history edited asd CC BY-SA 4.0
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May 26, 2019 at 16:47 history edited asd CC BY-SA 4.0
detailed explanation of how I used the hints given in the comments
May 26, 2019 at 16:42 history edited asd CC BY-SA 4.0
detailed explanation of how I used the hints given in the comments
May 26, 2019 at 16:35 history edited asd CC BY-SA 4.0
detailed explanation of how I used the hints given in the comments
May 25, 2019 at 22:42 answer added 2734364041 timeline score: 1
S May 19, 2019 at 9:29 history bounty started asd
S May 19, 2019 at 9:29 history notice added asd Draw attention
May 16, 2019 at 20:49 comment added asd I'm sorry, I cannot follow you. What should I do exactly?
May 16, 2019 at 20:25 comment added reuns Looking at $\psi_1(x)=\int_1^x \psi(y)dy, \sum_\rho \frac{x^\rho}{\rho(\rho+1)}, \frac{1}{s+1} \frac{\zeta'(s)}{\zeta(s)}, \sum_\rho \frac{1}{\rho+1} \frac{1}{s-\rho}$ is easier because everything converges absolutely,the density of zeros implies error terms when summing over the zeros up to $T$ and replacing $\int_1^\infty$ by $\int_1^N$ in the Mellin transform of $\psi_1(x)$ and its sum over zeros approximation
May 16, 2019 at 19:40 history edited asd CC BY-SA 4.0
improved formatting
May 16, 2019 at 18:42 history asked asd CC BY-SA 4.0