Timeline for Circular (bracelets) permutations with alike things(reflections are equivalent) using polya enumeration [closed]
Current License: CC BY-SA 4.0
16 events
when toggle format | what | by | license | comment | |
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Mar 7, 2022 at 13:40 | vote | accept | Damn it My Foot | ||
Jul 10, 2020 at 16:07 | history | closed |
Alex M. LSpice YCor Adam P. Goucher Mark Wildon |
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Jun 10, 2020 at 12:32 | review | Close votes | |||
Jul 10, 2020 at 16:07 | |||||
Jun 10, 2020 at 7:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Feb 11, 2020 at 5:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Oct 14, 2019 at 5:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jun 16, 2019 at 4:12 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 17, 2019 at 3:48 | answer | added | Damn it My Foot | timeline score: 0 | |
May 17, 2019 at 3:29 | comment | added | Damn it My Foot | Yes I understood. I mistook the cyclic group for dihedral group. I was kind of confused. Thanks for the comment. I now understand how to apply the formula. | |
May 17, 2019 at 2:20 | comment | added | Max Alekseyev | What thing? Cyclic indices are different for the cyclic and dihedral groups, but their arguments (ie. $a_d=p_d$ here) are the same. | |
May 17, 2019 at 2:04 | comment | added | Damn it My Foot | Then isn't it the same thing as above in the question? | |
May 17, 2019 at 2:02 | comment | added | Max Alekseyev | In your case $a_d=p_d$. | |
May 17, 2019 at 1:53 | comment | added | Damn it My Foot | What is $a_d$ in that? Here $p_d$ is $\Sigma x_n^d$ | |
May 16, 2019 at 17:46 | comment | added | Max Alekseyev | Just use the cycle index of the dihedral group rather than that of the cyclic group. | |
May 16, 2019 at 17:01 | review | First posts | |||
May 16, 2019 at 17:19 | |||||
May 16, 2019 at 17:01 | history | asked | Damn it My Foot | CC BY-SA 4.0 |