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Jul 24, 2010 at 19:26 comment added Will Jagy Live and learn. $$ 2^{\sqrt 2} $$ was first proved transcendental by Kuzmin in 1930, so it was a near thing. en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_constant which also discusses David's example.
Jul 24, 2010 at 19:21 comment added Will Jagy $$ 2^{\sqrt 2} $$ is transcendental by Gelfond-Schneider. Therefore $$ {\sqrt 2}^{\sqrt 2} = \left( 2^{\frac{1}{2 }} \right)^{\sqrt 2} = \left( 2^{\sqrt 2} \right)^{\frac{1}{2 }} $$ is transcendental. en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_theorem $$ $$ On this and related topics, I really like "Irrational Numbers" by Ivan Niven, available in paperback from the M.A.A. Gelfond-Schneider and Hermite-Lindemann are proved, history given etc.
Jul 24, 2010 at 12:55 comment added Lennart Meier But it's cool, anyhow.
Jul 24, 2010 at 7:45 comment added Martin Brandenburg I don't think that this conjecture is not solved.
Jul 24, 2010 at 3:29 history answered David Spivak CC BY-SA 2.5