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May 15, 2019 at 12:49 vote accept Pierre-Yves Gaillard
May 14, 2019 at 22:44 comment added Denis T That assumption was made in the title of question.
May 14, 2019 at 14:12 comment added Pierre-Yves Gaillard Thanks a lot! +1. In the contravariant case, does it suffice to replace $kX$ with its dual?
May 14, 2019 at 13:49 history edited David E Speyer CC BY-SA 4.0
edited body
May 14, 2019 at 13:30 comment added David E Speyer You are right, I was trying to simplify too fast. See if this works.
May 14, 2019 at 13:30 history undeleted David E Speyer
May 14, 2019 at 13:29 history edited David E Speyer CC BY-SA 4.0
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May 14, 2019 at 13:23 history deleted David E Speyer via Vote
May 14, 2019 at 13:22 comment added Achim Krause Is $\phi_k$ really a natural transformation? Doesn't $\phi_k(f(S)) = f(\phi_k(S))$ fail if $S$ has size bigger than $k$ and $f(S)$ has size smaller than $k$?
May 14, 2019 at 13:16 history answered David E Speyer CC BY-SA 4.0