Timeline for A bound using Cauchy formula
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 9, 2019 at 21:57 | comment | added | mamiladi | i'll check this formula, thanks for your help | |
| Jun 6, 2019 at 14:00 | review | Close votes | |||
| Jun 6, 2019 at 14:40 | |||||
| Jun 6, 2019 at 13:41 | comment | added | Carlo Beenakker | $$|f^{(n_0)}(u_0)|=(1-{u_0})^{{n_0}-1} (1-{t_0} {u_0})^{-{n_0}-2}$$ $$\left| \left(\log ^2(1-{u_0}) ({n_0} ({t_0}-1)-{t_0} {u_0}+{t_0})+\log (1-{u_0}) (({n_0} (-{t_0})+{n_0}+{t_0} ({u_0}-1)) \log (1-{t_0} {u_0})+{t_0} {u_0}+{t_0}-2)+(1-{t_0} {u_0}) \log (1-{t_0} {u_0})\right)\right|$$ --- not just an upper bound, but an exact evaluation as an explicit function of $u_0$, $t_0$, $n_0$ (this seems to satisfy what you are asking, correct me if I'm wrong). | |
| S Jun 6, 2019 at 10:44 | history | suggested | Glorfindel | CC BY-SA 4.0 |
typos corrected
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| Jun 6, 2019 at 9:07 | review | Suggested edits | |||
| S Jun 6, 2019 at 10:44 | |||||
| May 18, 2019 at 4:00 | history | edited | mamiladi | CC BY-SA 4.0 |
added 4 characters in body
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| May 13, 2019 at 6:44 | history | edited | Denis Serre | CC BY-SA 4.0 |
deleted 6 characters in body; edited title
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| May 13, 2019 at 4:40 | history | asked | mamiladi | CC BY-SA 4.0 |