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May 18, 2019 at 18:21 vote accept Taras Banakh
May 18, 2019 at 10:34 answer added TaQ timeline score: 3
May 11, 2019 at 11:51 answer added user131781 timeline score: 2
May 11, 2019 at 11:19 history edited Martin Sleziak
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May 11, 2019 at 11:18 comment added fedja It may be there in some form in the exercise sections, but who knows? Do you have any interesting corollaries you can derive from it? And yes, you are right: I was a bit sloppy when writing the conditions on $U_k$ :-)
May 11, 2019 at 11:14 answer added Jochen Wengenroth timeline score: 3
May 11, 2019 at 11:10 comment added Taras Banakh This fact should be true with a proof written by @fedja but with an extra-condition: $[-1,1]\cdot U_k\subset U_{k-1}$. Writing about "basic" fact, I did not have in mind that it is simple, but that it should be known and had to be included into basic textbooks dedicated to topological vectors spces.
May 11, 2019 at 10:59 comment added fedja In other words, you claim that for every fixed neighborhood of $0$ in $X$ there is a continuous semi-metric on $X$ whose open ball is contained in that neighborhood. If I haven't made a stupid mistake somewhere, this is certainly true: just take a sequence of symmetric neighborhoods $U_k$ where $U_0$ is your original neighborhood and $(k+1)(U_{k+1}+U_{k+1})\subset U_k$ and declare the distance between $x$ and $y$ to be $\inf\{\sum_i 2^{-k_i}:x-y=\sum z_i, z_i\in U_{k_i}\}$. However (if I haven't made a mistake) it is rather a qualifier exam problem than a basic fact. Am I missing anything?
May 11, 2019 at 6:36 history asked Taras Banakh CC BY-SA 4.0