Timeline for Looking for bound in integral involving Legendre polynomial
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
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May 26, 2019 at 0:57 | history | edited | mamiladi | CC BY-SA 4.0 |
deleted 2 characters in body
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May 17, 2019 at 0:16 | vote | accept | mamiladi | ||
May 11, 2019 at 13:01 | comment | added | mamiladi | thanks mr Fedor petrov for your quick answer, i'm sorry because my question wasn't clear, in fact i'm looking to constant $ 0<c<1$ independent of $n$ such that $I_n<b*c^n$ whith $b$ is a constant independant of $n$ . an equivalent to $(I_n)^(1/n)$ will be perfect for me | |
May 11, 2019 at 9:44 | comment | added | EGME | @FedorPetrov I get the same as you (also with Mathematica) | |
May 11, 2019 at 9:35 | comment | added | Fedor Petrov | @user64494 for $n=1$ I get $\int_0^1 \int_0^1 (1-2x)(1-2y)/(1-xy)=5\pi^2/6-8\approx 0.22467$ | |
May 11, 2019 at 9:09 | answer | added | Fedor Petrov | timeline score: 6 | |
May 11, 2019 at 8:55 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
minor typos
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S May 11, 2019 at 8:52 | history | suggested | user64494 | CC BY-SA 4.0 |
A typo in the title is corrected.
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May 11, 2019 at 8:20 | comment | added | user64494 | Here are some values fro 1 to 50 with step 3 done with Mathematica: ${0.644934066848, 0.0506357428594, 0.0193926015722, 0.00909693982500, \ 0.00575435101450, 0.00367705114317, 0.00271759837650, \ 0.00197640380654, 0.00157689618165, 0.00123156302281, \ 0.00102844646947, 0.000840349805475, 0.000723315503534, \ 0.000609762183667, 0.000536278083883, 0.000462537723680, \ 0.000413413530462}$. | |
May 11, 2019 at 8:17 | review | Suggested edits | |||
S May 11, 2019 at 8:52 | |||||
S May 11, 2019 at 7:39 | history | edited | András Bátkai | CC BY-SA 4.0 |
formatted, tag changed
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May 11, 2019 at 6:51 | review | Suggested edits | |||
S May 11, 2019 at 7:39 | |||||
May 11, 2019 at 1:06 | history | asked | mamiladi | CC BY-SA 4.0 |