Timeline for Compute $ \partial_t\int_{\{u(t,\cdot) >0\} } 1\, dx$ in the sense of distributions where $u$ solves a PDE
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
May 18, 2019 at 14:58 | comment | added | Jay | I've asked a very closely related question on some aspects of your answer on Mathematics StackExchange: math.stackexchange.com/questions/3226098/… | |
May 11, 2019 at 13:38 | comment | added | Carlo Beenakker | yes, the derivative diverges; I'm not sure what you mean by the "test function"; all of these manipulations are in distributional sense | |
May 11, 2019 at 13:35 | comment | added | Jay | Do you mean that in that case the derivative blows up? | |
May 11, 2019 at 13:24 | comment | added | Carlo Beenakker | if the derivative vanishes there is no finite answer; for the same reason that $\int \delta(x^2)dx$ diverges. | |
May 11, 2019 at 12:43 | comment | added | Jay | Also: (1) is there anything we can do if the gradient does vanish on $S(t)$? (2) what is the relationship between the last formula and the distributional derivative of the function, i.e. $\langle \int_{\{u(t,\cdot) >0\}} 1 dx, \partial_t \phi \rangle$? (since $\partial_t u$ is to be intended in the distributional sense). | |
May 11, 2019 at 12:36 | comment | added | Jay | Maybe I got it: do you mean that $S(t)$ is the "interface" (i.e. the boundary of the support)? | |
May 11, 2019 at 10:29 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 666 characters in body
|
May 10, 2019 at 20:48 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
added 367 characters in body
|
May 10, 2019 at 20:16 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |