Timeline for The expectation of partition times needed separate two elements in a set
Current License: CC BY-SA 4.0
8 events
when toggle format | what | by | license | comment | |
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May 13, 2019 at 12:59 | vote | accept | oNgStrIng | ||
May 10, 2019 at 16:48 | history | edited | Andrés E. Caicedo |
edited tags
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May 10, 2019 at 14:10 | answer | added | Pat Devlin | timeline score: 4 | |
May 10, 2019 at 13:50 | history | edited | oNgStrIng | CC BY-SA 4.0 |
clarification
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May 10, 2019 at 13:48 | comment | added | oNgStrIng | Hi @Devlin Each, partition will perform on the particular subset containing $s_1,s_2$, since if $s_1,s_2$ are separated, the partition process will stop. So I think (a) is not. The block, i.e. the subset, is the very one, not random. So (b) is not. It seems that (c) is also not. I will re-edit and clarify the process. | |
May 10, 2019 at 13:41 | comment | added | Pat Devlin | Could you elaborate on the random process? Here are a few options about what you could mean. (a) At each step, refine the partition by picking a block and splitting it into two blocks. Among all such partitions, pick uniformly at random [so big blocks are more likely to be split up]. Or perhaps you mean (b) do (a), but first pick the block to split up with each block being equally likely. Or perhaps you mean the very different (c) pick sets S_1, S_2, S_3, ... independently uniformly at random [with/without replacement], and consider minimal non-empty sets in the topology generated by them. | |
May 10, 2019 at 12:25 | review | First posts | |||
May 10, 2019 at 12:39 | |||||
May 10, 2019 at 12:23 | history | asked | oNgStrIng | CC BY-SA 4.0 |