Timeline for Why is this test function admissible? [Paper explanation]
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| May 9, 2019 at 17:44 | comment | added | DCM | "Thus $\psi(u_n(t))\chi_{(0,t)}$is basically the function we use to integrate against $P(u_n), f_n$ and for that reason the wide term "test function" is adopted." - that is my understanding yes. | |
| May 9, 2019 at 11:22 | vote | accept | kaithkolesidou | ||
| May 9, 2019 at 8:20 | comment | added | kaithkolesidou | First of all, thank you very much for your time and your reply. Now, if I understood correctly, in the case of this paper $\psi(u_n(t))\chi_{(0,t)}$ is a distribution and since $(u_n)$ and $(f_n)$ are considered as test functions in the traditional sense, the duality pairing is satisfied. Thus $\psi(u_n(t))\chi_{(0,t)}$ is basically the function we use to integrate against $P(u_n),f_n$ and for that reason the wide term "test function" is adopted. Am I right? | |
| May 8, 2019 at 22:16 | history | answered | DCM | CC BY-SA 4.0 |