Timeline for Every symplectic submanifold is J-holomorphic
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| May 9, 2019 at 14:32 | comment | added | Mohan Swaminathan | We are choosing a (compatiblle) fibrewise complex structure on the $\omega$-orthogonal complement $TN^\omega\subset TM|_N$. Said another way, we are reducing the structure group of $TM|_N = TN\oplus TN^\omega$ from $Sp(2n)$ to $U(n)$ by doing it for each direct summand separately. | |
| May 9, 2019 at 14:29 | comment | added | cr1t1cal | Wouldn't you need to choose a compatible almost complex structure on the symplectic normal bundle for which the zero-section is J-holomorphic? Why is that always possible? | |
| May 7, 2019 at 22:36 | vote | accept | cr1t1cal | ||
| May 7, 2019 at 22:28 | history | answered | Mohan Swaminathan | CC BY-SA 4.0 |