Timeline for Harmonic functions vanishing on the boundary and distance function asymptotics
Current License: CC BY-SA 4.0
9 events
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May 8, 2019 at 9:34 | comment | added | Liviu Nicolaescu | Think of the special situation in my answer when $\Omega$ is the unit disk in the plane and f$u$ is radially symmetric. Look at the Taylor expansion in $r$ near $r=1$, $$u=u(1)+\partial_r(1)(r-1)+\partial^2_ru(1)(r-1)^2/2+O(\;(r-1)^3\;),$$ where $|r-1|={\rm dist}\;(x,\partial \Omega)$, $\partial_r=\partial_\nu$. | |
May 8, 2019 at 9:27 | comment | added | Liviu Nicolaescu | Think Taylor expansion in normal direction. | |
May 8, 2019 at 7:01 | comment | added | user139845 | Why do you need that? | |
May 8, 2019 at 0:35 | comment | added | Liviu Nicolaescu | You also need $\frac{\partial^2 u}{\partial \nu^2}\neq 0$. | |
May 8, 2019 at 0:33 | history | edited | Liviu Nicolaescu | CC BY-SA 4.0 |
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May 7, 2019 at 22:23 | comment | added | user139845 | For example, what if we require also $\nabla u = 0$ on $\partial \Omega$? | |
May 7, 2019 at 20:16 | comment | added | user139845 | Is there any way to recover the square under additional assumptions? | |
May 7, 2019 at 20:16 | history | edited | Liviu Nicolaescu | CC BY-SA 4.0 |
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May 7, 2019 at 20:07 | history | answered | Liviu Nicolaescu | CC BY-SA 4.0 |