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May 6, 2019 at 20:54 vote accept user267839
May 6, 2019 at 15:05 history edited Sean Lawton CC BY-SA 4.0
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May 6, 2019 at 14:46 answer added Sean Lawton timeline score: 3
May 6, 2019 at 3:53 answer added user130124 timeline score: 1
May 6, 2019 at 3:43 comment added user267839 Another remark: I think that in case of $\mathbb{C}^2/\mathbb{C}^*$ the fact that Zariski topology has the Kolmogorov property en.wikipedia.org/wiki/Kolmogorov_space does it's job. indeed there exist no open set which contains a line $(\lambda x, \lambda y)$ but not the origin $\{(0,0)\}$. But in case of $\mathbb{A}^1/G_m$ it seems to be a bit more subtle: the "point"/orbit $\mathbb{A}^1/G_m - \{0\}$ is open so it can be separated from point $\{0\}$ in Kolmogorov's way. So what fails in case $\mathbb{A}^1/G_m$?
May 6, 2019 at 2:34 comment added user267839 To simplify the problem: I think essentially the same argument that the author gave in his example would show that if we let act the multiplicative variety $G_m$ on $\mathbb{A}^1$. Then the topological quotient $p: \mathbb{A}^1 \to \mathbb{A}^1/G_m$ should also fail to become a variety. Another idea: If we assume that the topological quotient $\mathbb{A}^1/G_m$ has a variety structure, should all orbits /point be closed? Why? If yes, this would lead to the desired contradiction but I don't see an argument why we can make this assumption.
May 6, 2019 at 2:18 comment added user267839 @gcousin: I'm not sure. We consider the underlying topological space endowed with Zariski topology so unless for finite algebraic sets no algebraic set is ever a Hausdorff space. Or do I oversee an aspect?
May 6, 2019 at 2:02 comment added gcousin I imagine the main point is that the topological space underlying a complex variety should be Hausdorff
May 6, 2019 at 1:35 review Close votes
May 6, 2019 at 20:44
May 6, 2019 at 1:23 history edited user267839 CC BY-SA 4.0
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May 6, 2019 at 1:18 comment added LSpice This is a good question, but probably not research level. It might be better at MSE.
May 6, 2019 at 1:09 history asked user267839 CC BY-SA 4.0