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Jul 27, 2010 at 0:19 vote accept CommunityBot
Jul 27, 2010 at 0:19
Jul 24, 2010 at 2:01 comment added Daniel Mehkeri Okay, so how about the converse? Given such a set S, can we find an ordinal with uncountable cofinality? Perhaps just take its rank? If that is correct, then, combining that with François' answer, I would conclude the answer to the original question is «no», ZF cannot prove the existence of such an S.
Jul 23, 2010 at 18:18 history edited Joel David Hamkins CC BY-SA 2.5
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Jul 23, 2010 at 11:44 history answered Joel David Hamkins CC BY-SA 2.5