Timeline for A Singular Foliation of $\mathbb{C}P^2$ which does not admit a global transverse submanifold
Current License: CC BY-SA 4.0
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| May 24, 2019 at 7:51 | comment | added | Ali Taghavi | However your argument assume that $S$ is compact otherwise we can not speak about a finite $d$. am i right? it is possible an immersed 9not embedded) holomorphic curve has infinite number of holes, Yes? moreover you assume that $S$ never intersect a singularity. So what about if we allow $S$ to intersect some singularities but at regular points the intersection would be transversal? | |
| May 24, 2019 at 7:49 | comment | added | Ali Taghavi | math.stackexchange.com/questions/116040/… | |
| May 24, 2019 at 7:48 | comment | added | Ali Taghavi | Thank you again for your very interesting answer. i confess that it was difficult for me to understand the details of your great answer. I need to more effort for a complete understanding but the following two links help me to get the sketch of your proof. or example this link help me to see $c_1(F)\leq 1$ qcpages.qc.cuny.edu/~zakeri/papers/SHFC_zak.pdf and this MSE post help me to see the reason of "$3$" in "$3d$" in the left part of your formula (1) | |
| May 24, 2019 at 7:43 | vote | accept | Ali Taghavi | ||
| May 6, 2019 at 16:26 | comment | added | Dmitri Panov | Sure, Ali, please ask if you want to clarify something | |
| May 5, 2019 at 18:27 | comment | added | Ali Taghavi | Thank you very much for your answer. I try to understand its details. | |
| May 5, 2019 at 1:04 | history | edited | Dmitri Panov | CC BY-SA 4.0 |
added 416 characters in body
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| May 5, 2019 at 0:53 | history | answered | Dmitri Panov | CC BY-SA 4.0 |