Timeline for Mahler measures of values of polynomials
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| May 6, 2019 at 19:09 | comment | added | Joe Silverman | There is a lower bound $H(f(\alpha))\ge CH(\alpha)^n$, but note that the implied constant will depend on $f$, as it will for the upper bound. | |
| May 6, 2019 at 13:20 | comment | added | Maurizio Moreschi | The bound you prove can actually be improved to $H(f(\alpha))\le C H(\alpha)^n$ (which is what I was aiming for) under the assumption of my question. I post the proof of this as an answer, because it is too long for a comment. | |
| May 3, 2019 at 2:26 | history | edited | Bobby Grizzard | CC BY-SA 4.0 |
added 163 characters in body
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| May 3, 2019 at 2:18 | history | answered | Bobby Grizzard | CC BY-SA 4.0 |