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May 2, 2019 at 21:57 vote accept FKranhold
May 2, 2019 at 7:57 answer added AGenevois timeline score: 9
May 1, 2019 at 20:50 review Close votes
May 2, 2019 at 13:20
May 1, 2019 at 16:49 comment added YCor Yes it's injective, because the image in the abelianization of $F_n$ of $\varphi(F_n)$ is all of $\mathbf{Z}^n$, and hence $\varphi(F_n)$ has rank $\ge n$, and every surjective endomorphism of $F_n$ is injective.
May 1, 2019 at 16:31 comment added Arturo Magidin @AniruddhAgarwal: They are conjugating each generator by a different word.
May 1, 2019 at 16:21 comment added Aniruddh Agarwal Am I missing something: isn't conjugation always an automorphism?
May 1, 2019 at 16:17 history asked FKranhold CC BY-SA 4.0