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Apr 30, 2019 at 15:13 vote accept yarchik
Apr 30, 2019 at 12:34 history became hot network question
Apr 30, 2019 at 12:17 answer added fedja timeline score: 12
Apr 30, 2019 at 11:20 history edited yarchik CC BY-SA 4.0
The formulation was vague on several points. Now they are all made more precise thanks to users' comments.
Apr 30, 2019 at 10:01 history edited yarchik CC BY-SA 4.0
fixed wording
Apr 30, 2019 at 9:59 history edited Martin Sleziak
added the (traces) tag
Apr 30, 2019 at 9:58 history edited yarchik CC BY-SA 4.0
The question is made more precise.
Apr 30, 2019 at 9:02 comment added Josiah Park @yarchik Allowing for multiple $\Gamma$'s allows for a positive answer. For instance for $n=3$ if one takes $\Gamma_{i}=e_{i}e_{i}^{T}$, $i=1,\dots,3$ one can recover $A$.
Apr 30, 2019 at 9:01 comment added yarchik @JosiahPark Indeed $\Gamma=I$ is somewhat a special case. The problem may also be ill posed for $\Gamma$ in the vicinity of $I$. It is my hope, however, solutions may be found for some $\Gamma$.
Apr 30, 2019 at 8:57 comment added yarchik @user44191 Can you please elaborate about the conjugacy classes?
Apr 30, 2019 at 8:47 history edited Francesco Polizzi
edited tags
Apr 30, 2019 at 8:45 comment added user44191 If $B$ is a nonsingular matrix that commutes with $\Gamma$, then $B^{-1}AB$ will have the same traces; assuming that $\Gamma$ has distinct eigenvalues, these $B$ are arbitrary diagonal matrices. It may still be possible to determine the $C_G(\Gamma)$-conjugacy class $A$ belongs to in $\mathbb{M}_n$ (though I haven't checked fully).
Apr 30, 2019 at 8:45 comment added Josiah Park It is not true for $\Gamma=I$. Since $Tr(A^k)=\sum\limits_{i=1}^n \lambda_{i}^k$, no additional information can be retrieved besides the eigenvalues (which are already given).
Apr 30, 2019 at 8:45 answer added Francesco Polizzi timeline score: 5
Apr 30, 2019 at 8:11 history asked yarchik CC BY-SA 4.0