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May 1, 2019 at 11:35 comment added Emil Jeřábek In this construction, you can take $N=O(n^2)$, see e.g. en.wikipedia.org/wiki/… .
May 1, 2019 at 2:38 history edited Brendan McKay CC BY-SA 4.0
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Apr 30, 2019 at 21:53 comment added bof I don't know anything about uncountable tournaments, but your construction seems to work fine in the countable case. In fact there is one vertex-transitive countable tournament which contains a copy of every countable tournament. Namely, the random countable tournament contains a copy of every countable tournament, so it suffices to embed the random tournament in an "infinite cyclic tournament".
Apr 30, 2019 at 11:45 history edited Brendan McKay CC BY-SA 4.0
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Apr 30, 2019 at 8:23 comment added Andreas Thom My answer is also about finite tournaments, but it asks for more, namely the property that all partially defined automorphisms can be extended. The resulting tournament would be also edge-transitive etc.
Apr 30, 2019 at 6:55 history answered Brendan McKay CC BY-SA 4.0