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Apr 30, 2019 at 0:11 vote accept Joseph O'Rourke
Apr 29, 2019 at 12:43 comment added Tony Huynh @JeppeStigNielsen: You can increase the length from $100$ to an arbitrarily large length, in which case it is clear that the bottom picture covers less area.
Apr 29, 2019 at 11:52 comment added Joseph O'Rourke @JeppeStigNielsen: "more upright": Yes, about $65^\circ$. See added detail.
Apr 29, 2019 at 11:51 history edited Joseph O'Rourke CC BY-SA 4.0
added 280 characters in body
Apr 29, 2019 at 10:07 comment added Jeppe Stig Nielsen The first packing is $100\cdot (10+1) = 1100$, but I think the second packing is $\left( \frac{10}{61}(11+6\sqrt{22})+100 \right)\cdot 10\approx 1064.2$, so the example is valid, but $1025$ from the original comment is not so precise. To me, it is hard to estimate visually by staring at the figure, which packing is better, but I can see that the "leaning" thin box is more upright than $45^\circ$.
Apr 27, 2019 at 19:55 comment added Joseph O'Rourke @VictorProtsak: Thanks; corrected.
Apr 27, 2019 at 19:54 history edited Joseph O'Rourke CC BY-SA 4.0
edited body
Apr 27, 2019 at 19:51 comment added Victor Protsak Actually, in the first packing the smaller rectangle should lie on the top of the larger one, giving the intended area of 11*100=1100.
S Apr 27, 2019 at 19:16 history answered Joseph O'Rourke CC BY-SA 4.0
S Apr 27, 2019 at 19:16 history made wiki Post Made Community Wiki by Joseph O'Rourke