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David E Speyer
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CP^2 is not a curve. So you may have misstated your question. Nonetheless, here is my answer:

Every curve of genus 1 is a principal homogenous space for its Jacobian. Over an algebraically closed field, a principal homogenous space is just the group itself, and that is what happens in this case.

For genus g >= 2, no algebraic curve has more than 84(g-1) algebraic automorphisms. In particular, no curve can be a homogenous space.

EDIT The comment about CP^2 refers to an earlier version of the question.

CP^2 is not a curve. So you may have misstated your question. Nonetheless, here is my answer:

Every curve of genus 1 is a principal homogenous space for its Jacobian. Over an algebraically closed field, a principal homogenous space is just the group itself, and that is what happens in this case.

For genus g >= 2, no algebraic curve has more than 84(g-1) algebraic automorphisms. In particular, no curve can be a homogenous space.

CP^2 is not a curve. So you may have misstated your question. Nonetheless, here is my answer:

Every curve of genus 1 is a principal homogenous space for its Jacobian. Over an algebraically closed field, a principal homogenous space is just the group itself, and that is what happens in this case.

For genus g >= 2, no algebraic curve has more than 84(g-1) algebraic automorphisms. In particular, no curve can be a homogenous space.

EDIT The comment about CP^2 refers to an earlier version of the question.

Source Link
David E Speyer
  • 156.3k
  • 14
  • 422
  • 763

CP^2 is not a curve. So you may have misstated your question. Nonetheless, here is my answer:

Every curve of genus 1 is a principal homogenous space for its Jacobian. Over an algebraically closed field, a principal homogenous space is just the group itself, and that is what happens in this case.

For genus g >= 2, no algebraic curve has more than 84(g-1) algebraic automorphisms. In particular, no curve can be a homogenous space.