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Apr 24, 2019 at 16:04 vote accept Alan Muniz
Apr 23, 2019 at 4:27 answer added Sasha timeline score: 6
Apr 22, 2019 at 23:30 comment added Sándor Kovács Since $\mathcal{Ext}^1_{\mathcal{O}_X}(F/E, \mathcal{O}_X)$ is supported on $Z$, $N=\mathcal{Ext}^1_{\mathcal{O}_X}(F/E, \mathcal{O}_X)$ (or you can add "restricted to $Z$") should work, no? So, this does not simplify the computation....
Apr 22, 2019 at 21:51 history asked Alan Muniz CC BY-SA 4.0