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Apr 22, 2019 at 23:42 comment added Laithy never-mind, I think I made a mistake; the $O (r^{-3})$ should not be there. Also, Robert gave an example.
Apr 22, 2019 at 21:52 comment added Laithy Thank you so much. Following this method, I am getting that one solution is $-\frac1r + O (r^{-3})$ and the other is as you said $O (r^{-2})$. Did you get that too? Also, to what can I relax analyticity at infinity so I can get the same conclusion?
Apr 22, 2019 at 21:49 vote accept Laithy
Apr 22, 2019 at 19:09 history edited Alexandre Eremenko CC BY-SA 4.0
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Apr 22, 2019 at 18:50 history answered Alexandre Eremenko CC BY-SA 4.0