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Apr 25, 2019 at 20:11 comment added Carlo Beenakker no, but the MSE answer I linked to has a proof, you could just cite that if you would need to...
Apr 25, 2019 at 17:55 comment added B Merlot Do you know of a reference book/paper where this fact about the condition number is shown?
Apr 22, 2019 at 15:19 vote accept fewfew4
Apr 22, 2019 at 15:19 comment added fewfew4 @MichaelSeifert Yes I am also noticing that my $4\times4$ case does not satisfy the condition I was trying to make hold.
Apr 22, 2019 at 14:17 comment added Michael Seifert Note that the OP's equation for the $n = 3$ case agrees with the equation from the notes in the case where $K$ has two identical eigenvalues. I don't think this is true of the OP's $n = 4$ case, though (in either the case where $K$ has two "double" eigenvalues or in the case where it has one "single" and one "triple" eigenvalue.)
Apr 22, 2019 at 11:35 history edited Carlo Beenakker CC BY-SA 4.0
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Apr 22, 2019 at 7:29 history edited Carlo Beenakker CC BY-SA 4.0
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Apr 22, 2019 at 7:12 history answered Carlo Beenakker CC BY-SA 4.0