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Timeline for Equivariant maps of "higher order"

Current License: CC BY-SA 2.5

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Jul 21, 2010 at 20:18 comment added Bugs Bunny Yeah, sure, as Tom has redefined the same thing. My point is that it happens to have a name "differential operator", which partially answers the usefullness non-question.
Jul 21, 2010 at 20:01 comment added Mariano Suárez-Álvarez You get differential operators if you consider (in the context of Tom's answer) $I$ to be the kernel of the augmentation $A\otimes_RA\to A$ given by multiplication.
Jul 21, 2010 at 19:37 history answered Bugs Bunny CC BY-SA 2.5