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Post Closed as "Not suitable for this site" by user44191, Sean Lawton, Jan-Christoph Schlage-Puchta, Pace Nielsen, Sebastian Goette
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Dreamer123
Dreamer123
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Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint cubesparts.

Is there a method how can one do that?

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint cubes.

Is there a method how can one do that?

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint parts.

Is there a method how can one do that?

edited body
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Dreamer123
Dreamer123
  • 139
  • 4

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint partscubes.

Is there a method how can one do that?

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint parts.

Is there a method how can one do that?

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint cubes.

Is there a method how can one do that?

Source Link
Dreamer123
Dreamer123
  • 139
  • 4

Is there a method to cut a hypercube into disjoint cubes

Since Borsuk conjecture hold for centrally symmetric convex sets in $\mathbb{R}^n$ so we can cut a hypercube into at least $n+1$ disjoint parts.

Is there a method how can one do that?