Timeline for Questions about "The best card trick"
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 16, 2019 at 2:33 | vote | accept | David G. Stork | ||
| Apr 16, 2019 at 2:09 | history | edited | Tony Huynh | CC BY-SA 4.0 |
added 8 characters in body
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| Apr 16, 2019 at 2:02 | history | edited | Tony Huynh | CC BY-SA 4.0 |
added 288 characters in body
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| Apr 16, 2019 at 1:49 | comment | added | David G. Stork | OK. Thanks. Makes sense. (+1)... and await the full answer to both questions for a $\checkmark$. | |
| Apr 16, 2019 at 1:47 | comment | added | Tony Huynh | I am counting 4-tuples that cannot occur, so $e$ is $b, c$, or $d$. | |
| S Apr 16, 2019 at 1:45 | history | suggested | David G. Stork | CC BY-SA 4.0 |
Simplified the first equation
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| Apr 16, 2019 at 0:41 | review | Suggested edits | |||
| S Apr 16, 2019 at 1:45 | |||||
| Apr 16, 2019 at 0:15 | comment | added | David G. Stork | Thanks... but I'm a little confused by your answer. Could you explain why in your last sentence this issue is the "unique ordering $(b,c,d)$ of $\{x,y,e\}$"? As you rightly point out, $e$ can never be in the exposed 4-tuple, so the ordering of it among $(b,c,d)$ seems inappropriate. | |
| Apr 15, 2019 at 23:16 | history | edited | Tony Huynh | CC BY-SA 4.0 |
deleted 3 characters in body
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| Apr 15, 2019 at 23:10 | history | answered | Tony Huynh | CC BY-SA 4.0 |