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Aug 17, 2019 at 9:50 answer added Victor Ivrii timeline score: 4
Apr 16, 2019 at 16:54 comment added Hadrian Quan Apologies for not realizing you meant this. I think you're right, as the principal symbol in classical calculus he considers will not include the potential $V(x)$ (I suppose this is the point of considering semiclassical operators!) I am glad you were able to find some references.
Apr 16, 2019 at 15:58 answer added Maxim Braverman timeline score: 4
Apr 16, 2019 at 15:21 comment added Maxim Braverman @HadrianQuan Clearly, I assume that $V(x)$ grows at infinity, so that the volume in (**) is finite. I did look at Hormander. I don't think the result I need follows from it.
Apr 14, 2019 at 17:24 comment added Hadrian Quan I don't think completeness alone will suffice to say anything this general. E.g. there are complete riemannian manifolds with purely continuous spectrum (such as the upper half-plane $\mathbb{H}^2$ has spectrum $[1/4,\infty)$.) If you're not considering closed manifolds, and you don't assume something about how your potential $V(x)$ behaves at infinity I don't think you can hope to get a Weyl Law. You might look at H\"{o}rmander's "spectral function of an elliptic operator" since he proves a weyl law very generally, though at the cost of some FIO theory being necessary.
Apr 14, 2019 at 6:44 comment added Josiah Park Victor Ivrii is somewhat responsive to emails. One could try emailing the question to him for a response.
Apr 13, 2019 at 15:52 history edited Maxim Braverman CC BY-SA 4.0
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Apr 12, 2019 at 18:42 history asked Maxim Braverman CC BY-SA 4.0