Timeline for Generating the digits in a base system by repeated multiplication of a number
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Apr 10, 2019 at 6:30 | comment | added | Gerry Myerson | @Bullet, sure, and if you had written, all possible digits in $0,\dots,b-1$ occur as second digits, I would have had no objection. | |
Apr 10, 2019 at 4:26 | comment | added | LeechLattice | @GerryMyerson But zero could appear as second digit. The Weyl equidistribution law still applies. | |
Apr 10, 2019 at 3:26 | comment | added | Gerry Myerson | A distantly related and, I believe, unsolved problem is to show that for all sufficiently large $n$ there is a zero somewhere in the decimal representation of $2^n$. See, e.g., oeis.org/A238938 | |
Apr 10, 2019 at 3:23 | comment | added | Gerry Myerson | @Bullet, I'd say zero never occurs as first digit. | |
Apr 9, 2019 at 23:45 | comment | added | LeechLattice | For the second question, no. For any number $n$ and base $b$ with $log_b(n)$ irrational, $klog_b(n)$ for $k\geq1$ obeys the Weyl equidistribution law, hence all possible digits in $0...b-1$ occur as first digits. | |
Apr 9, 2019 at 23:45 | review | First posts | |||
Apr 10, 2019 at 0:35 | |||||
Apr 9, 2019 at 23:42 | history | asked | Matthew Lim | CC BY-SA 4.0 |