Timeline for Covering the primes with pairs of consecutive integers
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
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Apr 14, 2019 at 14:32 | vote | accept | Bernardo Recamán Santos | ||
Apr 10, 2019 at 5:46 | comment | added | Alexander Kalmynin | @FreddyBarrera Corrected, thanks | |
Apr 10, 2019 at 5:45 | history | edited | Alexander Kalmynin | CC BY-SA 4.0 |
edited body
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Apr 10, 2019 at 3:19 | comment | added | Freddy Barrera | I think it's $a=p-1$ or $a=p$ (in the first paragraph), right? | |
Apr 9, 2019 at 22:07 | comment | added | Alexander Kalmynin | I guess, the same argument works if $k<\pi(n)(1-\varepsilon)$ where $\varepsilon>0$ is fixed, but you need to consider primes between $\delta n$ and $n$ for some $\delta<\varepsilon$. | |
Apr 9, 2019 at 21:54 | history | answered | Alexander Kalmynin | CC BY-SA 4.0 |