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Apr 14, 2019 at 14:32 vote accept Bernardo Recamán Santos
Apr 10, 2019 at 5:46 comment added Alexander Kalmynin @FreddyBarrera Corrected, thanks
Apr 10, 2019 at 5:45 history edited Alexander Kalmynin CC BY-SA 4.0
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Apr 10, 2019 at 3:19 comment added Freddy Barrera I think it's $a=p-1$ or $a=p$ (in the first paragraph), right?
Apr 9, 2019 at 22:07 comment added Alexander Kalmynin I guess, the same argument works if $k<\pi(n)(1-\varepsilon)$ where $\varepsilon>0$ is fixed, but you need to consider primes between $\delta n$ and $n$ for some $\delta<\varepsilon$.
Apr 9, 2019 at 21:54 history answered Alexander Kalmynin CC BY-SA 4.0