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Apr 7, 2019 at 17:39 comment added macgucci @GregMartin, indeed $F(\sigma, T)$ seems to have nothing to do with zeos with real part $>\sigma$. But what of those with real part equal to $\sigma$ ?
Apr 7, 2019 at 17:32 comment added Greg Martin Let me rephrase then: what reason do you have to think that $F(\frac23,T)$ should know about zeros with real part $\frac34$?
Apr 7, 2019 at 17:30 comment added macgucci @GregMartin, i think that's exactly what my question is...
Apr 7, 2019 at 17:29 comment added Greg Martin Might it be possible that, for example, there are zeros of $\zeta$ with real part $\frac34$, yet $F(\frac23,T)$ is bounded?
Apr 7, 2019 at 17:17 history edited macgucci CC BY-SA 4.0
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Apr 7, 2019 at 17:00 review First posts
Apr 7, 2019 at 17:17
Apr 7, 2019 at 16:55 history asked macgucci CC BY-SA 4.0