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Apr 5, 2019 at 19:55 comment added James Dibble The argument doesn't require that $p$ be the unique zero of $X$. It's easy to see that this isn't essential; for example, consider the Killing field $X$ obtained as the variational derivative of rotation around a line in $\mathbb{R}^3$. Every point along the line will be a zero of $X$, and each orbit circle is equidistant from each point on the line.
Apr 5, 2019 at 5:33 comment added Shreya Also, do you mind telling where exactly uniqueness of point $p$ is being used?
Apr 5, 2019 at 3:48 comment added Shreya I'm sorry but we haven't done first variation formula in class, it's a problem in do Carmo's chapter 3 while he introduces curvature and such not before chapter 4 so I believe we could do it without using that.
Apr 5, 2019 at 0:53 history answered James Dibble CC BY-SA 4.0