Timeline for multiplier algebra of a simple $C^*$ algebra
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 5, 2019 at 1:05 | vote | accept | math112358 | ||
| Apr 5, 2019 at 0:15 | answer | added | Jamie Gabe | timeline score: 7 | |
| Apr 4, 2019 at 0:07 | comment | added | Yemon Choi | One possible idea for an attempted proof that the answer is "no": since $\prod_n {\bf M}_n$ is not exact as a $C^*$-algebra, one could try to show that $B$ being non-unital and simple implies that $M(B)$ contains a subalgebra isomorphic to $\prod_n {\bf M}_n$... | |
| S Apr 3, 2019 at 20:03 | history | edited | Alex M. | CC BY-SA 4.0 |
I add a tag.
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| S Apr 3, 2019 at 20:03 | history | suggested | Ali Taghavi |
I add a tag.
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| Apr 3, 2019 at 19:45 | review | Suggested edits | |||
| S Apr 3, 2019 at 20:03 | |||||
| Apr 3, 2019 at 17:45 | comment | added | Yemon Choi | My instinct is that multiplier algebras of any non-unital Cstar-algebra $B$ are usually "too big" to be nuclear, unless $B$ is close to being commutative e.g. $C_0(X; {\bf M}_2)$ which of course is very far from being simple. So I suspect the answer to your question is "no" but I don't see a proof at the moment | |
| Apr 3, 2019 at 17:28 | history | asked | math112358 | CC BY-SA 4.0 |