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Apr 4, 2019 at 6:08 history edited Jianrong Li
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Apr 2, 2019 at 15:55 vote accept Jianrong Li
Apr 1, 2019 at 20:52 answer added tj_ timeline score: 3
Apr 1, 2019 at 20:44 history edited Jianrong Li CC BY-SA 4.0
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Apr 1, 2019 at 20:42 comment added Jianrong Li @KConrad, thanks. Yes, I care about only the size of the kernel.
Apr 1, 2019 at 20:23 comment added KConrad You changed the question in a significant way (which is okay, since nobody really answered it yet). All you care about is the size of the kernel having a particular type of formula?
Apr 1, 2019 at 20:14 history edited Jianrong Li CC BY-SA 4.0
edited body
Apr 1, 2019 at 20:13 comment added Jianrong Li @tj_, thank you very much for your comments. They are not the same. I will edit the question.
Apr 1, 2019 at 19:04 comment added Sam Hopkins One obvious condition: $m$ is prime.
Apr 1, 2019 at 18:58 history edited Jianrong Li CC BY-SA 4.0
added 2 characters in body; edited title
Apr 1, 2019 at 18:55 comment added Jianrong Li @KConrad, thank you very much for your comments. I edited the question.
Apr 1, 2019 at 17:25 comment added KConrad Strictly speaking, $\ker(f) \subset \mathbf Z_m^4$ while $\mathbf Z_m^2$ is not in a canonical way a subgroup of $\mathbf Z_m^4$, so it is incorrect to say $\ker(f)$ equals $\mathbf Z_m^2$.
Apr 1, 2019 at 15:19 history asked Jianrong Li CC BY-SA 4.0