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Apr 1, 2019 at 17:22 vote accept Mare
Apr 1, 2019 at 16:23 comment added esg Ok, thanks (sorry, I should have noticed that). An amazing solution!
Apr 1, 2019 at 16:11 history bounty ended CommunityBot
Mar 31, 2019 at 17:54 history edited Gjergji Zaimi CC BY-SA 4.0
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Mar 31, 2019 at 17:13 comment added Gjergji Zaimi @esg: If the gcd is greater than 1, then there are multiple cycles in the quiver of that matrix.
Mar 31, 2019 at 16:52 comment added esg Small correction to Thm. 1 (I think): $\det(I+Z+\ldots+Z^{\omega(C)-1})$ will be $0$ if $1<\gcd(\omega(C),n)<n$ (so that you can get determinant $0$ also in the connected case).
Mar 31, 2019 at 8:04 history answered Gjergji Zaimi CC BY-SA 4.0