Timeline for Restriction of a Haar measure
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 12, 2019 at 2:05 | comment | added | B.Gillan | Tank you very much for your useful guidance. | |
| Mar 31, 2019 at 2:14 | comment | added | Nate Eldredge | It could also happen that $N$ is not compact. For instance, take $G = GL(n)$ and $H = O(n)$. Then $d_N(N)=\infty \ne d_H(H)$. | |
| Mar 31, 2019 at 1:59 | comment | added | Nate Eldredge | For the third question, assuming $N$ is compact, how do you normalize $d_N$? If $d_N$ is normalized Haar measure then the statement $d_H(H)=d_N(N)$ is trivial since they are both 1 by definition. | |
| Mar 31, 2019 at 1:48 | comment | added | Nate Eldredge | Frequently $H$ would have measure zero in $G$, so the restriction of $d_G$ to $H$ would yield the zero measure. For instance, $SO(n)$ as a subgroup of $GL(n)$. I think the construction you're looking for is not restriction but disintegration. | |
| Mar 31, 2019 at 1:39 | history | asked | B.Gillan | CC BY-SA 4.0 |