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Mar 28, 2019 at 9:48 vote accept GM1
Mar 28, 2019 at 7:54 answer added LeechLattice timeline score: 1
Mar 28, 2019 at 6:44 comment added GM1 I require $\Omega$ to be finite, so it can not be a circle.
Mar 28, 2019 at 2:04 comment added LeechLattice What if $y$ is the indicator function of a circle?
Mar 27, 2019 at 21:17 comment added GM1 I think the answer is positive and can be deduced from semanticscholar.org/paper/…, but I'm not sure at all. I guess that for any $y$ the set $y^{-1}(0)$ can be put inside a set of the form considered in that paper so that no point of $y^{-1}(1)$ is contained in it.
Mar 27, 2019 at 20:13 history edited GM1 CC BY-SA 4.0
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Mar 27, 2019 at 19:45 review First posts
Mar 27, 2019 at 19:46
Mar 27, 2019 at 19:40 history asked GM1 CC BY-SA 4.0