Timeline for Products and sum of cubes in Fibonacci
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 27, 2019 at 14:47 | comment | added | T. Amdeberhan | @NoamD.Elkies: Thanks for this approach too. | |
| Mar 26, 2019 at 20:00 | comment | added | Noam D. Elkies | Simpler yet: since $F_n = F_{n-1} + F_{n+2}$ it's enough to use the two-variable identity $(a+b)^3 - a^3 - b^3 = 3ab(a+b)$ which is a quick consequence of the binomial expansion of $(a+b)^3$. | |
| Mar 26, 2019 at 19:52 | history | answered | Cherng-tiao Perng | CC BY-SA 4.0 |