Skip to main content
broken link fixed, cf. https://meta.mathoverflow.net/q/5301/70594
Source Link
Glorfindel
  • 2.8k
  • 6
  • 28
  • 38

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paperThis paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paperpaper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

fixed link
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this notethis note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

fixed typo
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for all $b\leq 24$ $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b\leq 24$$b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for all $b\leq 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b\leq 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

There is a simple non-analytic proof for $p\equiv 1 \bmod n$; see e.g. Proposition $3$ in this note. The proof gives a (Euclidean) argument that infinitely many primes divide the values of an integer-coefficient polynomial on the integers, and then notes that the prime divisors of the values of the $n$-th cyclotomic polynomial either divide $n$ or have remainder $1$ upon division by $n$. (The proof is well-known; I don't know the originator.) By the way, the note also contains a cute analytic argument for $p\equiv 1 \bmod 4$ giving bounds on the partial sums of the reciprocals of such primes; the argument uses representations via sums of two squares.

Edit: This paper by Murty and Thain discusses obstructions to Euclid-style proofs for various congruence classes. I believe that a proof has been carried out for $p\equiv a\bmod b$ for $(a, b)=1$ for $b= 24$ in the style of Euclid, however.

Here is an open-access paper by Keith Conrad expositing this impossibility theorem and giving some background.

Edit 2: Here is the paper I recalled with the Euclidean proof for $b= 24$; unfortunately it is not open-access. It is JSTOR however so many of you likely have institutional access.

Cleanup
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144
Loading
Added another reference
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144
Loading
Added summary of proof.
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144
Loading
Added another paper
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144
Loading
Source Link
Daniel Litt
  • 23k
  • 5
  • 84
  • 144
Loading