Timeline for Partial sums of primes
Current License: CC BY-SA 4.0
33 events
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Apr 2, 2019 at 5:09 | comment | added | user44191 | @YemonChoi While the editing was annoying, it does seem to have stopped (last edit 5 days ago). | |
Apr 2, 2019 at 4:14 | comment | added | Yemon Choi | I'm voting to close this question because the OP persists in these edits. (I agree with GP and GM) | |
Apr 2, 2019 at 3:05 | review | Close votes | |||
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Mar 30, 2019 at 20:09 | comment | added | Enzo Creti | @Gerhard Paseman 7 is the 4th prime, 8263 is the 1036th prime. 7/7(sum of digits of 7)=1 and 4# has 1 digit. 8263/19(sum of digits of 8263) is truncated equal to 434...1036# has 434 digits where # is primorial function | |
Mar 28, 2019 at 21:30 | comment | added | Gerry Myerson | Version 16. Please, homunc, give it a rest. | |
Mar 28, 2019 at 18:54 | comment | added | Gerhard Paseman | I find these frequent edits go against the purpose of this forum. If you want to record frequent observations on a daily basis (whether they are significant or not), start a blog. You have asked a main question and gotten a reasonable answer; now move on. The numerology associated with the problem does not belong here. Next week, if you find a third prime satisfying the relations, you can report that here. Gerhard "Know When To Fold 'Em" Paseman, 2019.03.28. | |
Mar 28, 2019 at 18:09 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 28, 2019 at 15:24 | comment | added | Enzo Creti | $7$ is a Mersenne prime. $8263$ is the sum of five Mersenne primes $17$+$17$+$31$+$8191$+$31$+$7$. | |
Mar 28, 2019 at 14:52 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 28, 2019 at 7:56 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 27, 2019 at 21:35 | comment | added | Gerry Myerson | Now up to Version 13. | |
Mar 27, 2019 at 11:54 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 27, 2019 at 11:17 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 27, 2019 at 10:50 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 21:11 | comment | added | Gerry Myerson | Seven edits in the last 12 hours. | |
Mar 26, 2019 at 18:23 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 16:27 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 16:20 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 15:55 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 15:23 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 15:13 | comment | added | Alex M. | Possible duplicate of Why do primes dislike dividing the sum of all the preceding primes? | |
Mar 26, 2019 at 12:01 | comment | added | Enzo Creti | @Peter $8+2+6+3=19$. $8263+19-1=91^2$ where 91 is 19 reversed | |
Mar 26, 2019 at 9:22 | comment | added | Peter | The second solution ($8263$) has some amazing properties : The sum of its digits, the sum of the squares of its digits and the sum of the fifth powers of its digits are prime as well as $$8^8+2^2+6^6+3^3$$ | |
Mar 26, 2019 at 8:52 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 8:21 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
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Mar 26, 2019 at 8:17 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 26, 2019 at 7:40 | comment | added | Enzo Creti | @Alex M.@Mark Fischler the heuristic is the same for primes p(n) dividing the sum of primes up to p(n+1) and for primes p(n) dividing the sum of primes up to p(n). But it seems that in the first case primes are rarer. Why? | |
Mar 25, 2019 at 22:31 | comment | added | Alex M. | Strongly related: mathoverflow.net/questions/120511/…. Also crossposted on MSE: math.stackexchange.com/questions/3161810/23571113 (please don't do this anymore). | |
Mar 25, 2019 at 17:20 | history | became hot network question | |||
Mar 25, 2019 at 16:45 | review | Close votes | |||
Mar 26, 2019 at 20:33 | |||||
Mar 25, 2019 at 16:42 | answer | added | Mark Fischler | timeline score: 17 | |
Mar 25, 2019 at 16:12 | history | edited | Enzo Creti | CC BY-SA 4.0 |
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Mar 25, 2019 at 15:56 | history | asked | Enzo Creti | CC BY-SA 4.0 |