Timeline for On a problem for determinants associated to Cartan matrices of certain algebras
Current License: CC BY-SA 4.0
17 events
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Apr 1, 2019 at 17:22 | vote | accept | Mare | ||
| S Apr 1, 2019 at 16:11 | history | bounty ended | CommunityBot | ||
| S Apr 1, 2019 at 16:11 | history | notice removed | CommunityBot | ||
| Mar 31, 2019 at 8:04 | answer | added | Gjergji Zaimi | timeline score: 6 | |
| Mar 26, 2019 at 21:26 | comment | added | Mare | For $n$ odd and $w=(n+1)/2$ one can take $v=(0,0,0....,0,1)$ and for $n$ even and $w=(n+2)/2$ one can take $v$ with exactly two ones in position $n/2$ and $n$. | |
| Mar 26, 2019 at 21:07 | comment | added | Mare | @esg Yes, I think that this is easy. In fact the perfect $(w,v)$ for $n$ odd and $w=(n+1)/2$ seem to have a very nice pattern, but for $n$ even I have not figured out what the pattern might be yet. But the pattern is probably also very nice since the sequence oeis.org/A007051 has many nice interpretations. | |
| Mar 26, 2019 at 20:24 | comment | added | esg | Concerning conjecture 1: is it obvious or easy that the given maxima can be reached? Or is it part of the problem? | |
| S Mar 24, 2019 at 13:53 | history | bounty started | Mare | ||
| S Mar 24, 2019 at 13:53 | history | notice added | Mare | Draw attention | |
| Mar 23, 2019 at 21:22 | history | edited | Mare | CC BY-SA 4.0 |
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| Mar 23, 2019 at 20:35 | history | edited | Mare | CC BY-SA 4.0 |
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| Mar 22, 2019 at 18:27 | comment | added | MTyson | It might be useful to consider $M(t)=1+tZ+\cdots+(tZ)^{w-1}-D$. The determinant of $M(t)(1-tZ)=(1-D)+tDZ-t^wZ^w$ should have few nonzero terms. | |
| Mar 22, 2019 at 17:05 | history | edited | Mare | CC BY-SA 4.0 |
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| Mar 22, 2019 at 14:31 | history | edited | Mare | CC BY-SA 4.0 |
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| Mar 22, 2019 at 13:47 | history | edited | Mare | CC BY-SA 4.0 |
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| Mar 22, 2019 at 13:39 | history | asked | Mare | CC BY-SA 4.0 |